Saturday, 4 June 2016
On 03:22 by Unknown in Data and Network Security No comments
Example Mini-AES Encryption
The application of the four components NibbleSub, ShiftRow, MixColumn and KeyAddition in sequence constitutes one round. The full Mini-AES
encryption consists of two such rounds, with the exclusion of MixColumn from
the last round and the inclusion of an extra KeyAddition prior to the first
round. Hence, Mini-AES encryption can be
denoted by:
Mini-AESEncrypt = sK2 o p o g o sK1 o q o p o g o sK0
Note that the symbol o refers to the composition of
functions and the order of execution is from right to left, which means that sK0 is executed
first. Figure 7 provides a pictorial
view of Mini-AES encryption.
Figure 7: The Mini-AES Encryption Process
Example 9
To provide an illustrative example for the student, suppose that the input 16-bit plaintext block is P = 1001 1100 0110 0011. Expressed as a matrix of 2 ´ 2 of nibbles, it is then
Suppose also that the secret key, K = 1100 0011 1111 0000.
This is also expressed as a 2 ´ 2
matrix.
Firstly, the round keys are
derived from the secret key, K by way of the key schedule.
K0 = (w0,
w1, w2,
w3) = (k0,
k1, k2,
k3) = K = 1100 0011 1111 0000
K1 = (w4,
w5, w6,
w7) is calculated as follows:
w4 = w0 Å
NibbleSub( w3 ) Å 0001
= 1100 Å NibbleSub(0000) Å 0001
= 1100 Å 1110 Å 0001
= 0011
w5 =
w1 Å w4
= 0000
w6 = w2 Å w5
= 1111 Å 0000
= 1111
w7 = w3 Å w6
= 0000 Å 1111
= 1111
K2 = (w8,
w9, w10,
w11) is calculated as follows:
w8 = w4 Å
NibbleSub( w7 ) Å 0010
= 0011 Å NibbleSub(1111) Å 0010
= 0011 Å 0111 Å 0010
= 0110
w9 = w5 Å w8
= 0000 Å 0110
= 0110
w10 = w6 Å w9
= 1111 Å 0110
= 1001
w11 = w7 Å w10
= 1111 Å 1001
= 0110
Encryption of the Plaintext
Next, we proceed
with encryption. Given plaintext, P = 1001 1100 0110 0011, then after the first
KeyAddition with the 0th round
key, K0, the output is
A = P Å K0 =
1001 1100 0110 0011 Å 1100 0011 1111 0000
= 0101 1111 1001 0011
Round 1
After NibbleSub, the output is
B =
NibbleSub(0101), NibbleSub(1111), NibbleSub(1001), NibbleSub(0011)
= 1111 0111 1010 0001
After ShiftRow, the output is
C =
ShiftRow (1111 0111 1010 0001)
= 1111 0001 1010 0111
MixColumn is a bit more involved. The input block is
rearranged as a 2 ´ 2 matrix, hence:
Taking the first column and
multiplying it with the constant matrix, we get:
Taking the second column and
multiplying it with the constant matrix, we get:
Therefore, the output after MixColumn is
or D = 0000 1110 0011 1110
After KeyAddition with K1, the output
is
E = D Å K1 =
0000 1110 0011 1110 Å 0011 0000 1111 1111
= 0011 1110 1100 0001
After NibbleSub, the output is
F = NibbleSub(0011),
NibbleSub(1110), NibbleSub(1100), NibbleSub(0001)
= 0001 0000 0101 0100
After ShiftRow, the output is
G =
ShiftRow (0001 0000 0101 0100)
=
0001 0100 0101 0000
Note
that in the last round, there is no MixColumn. After KeyAddition, the output is
H = G Å K2 = 0001 0100 0101 0000 Å 0110 0110 1001 0110
= 0111 0010 1100 0110
Therefore, the final ciphertext is
H = 0111 0010 1100 0110
Mini-AES Decryption
In order to get
back the original plaintext, the reverse process of encryption must be performed on the ciphertext. This is called
decryption. Noting that decryption is
the inverse of encryption, then
Mini-AESDecrypt = (sK2 o p o g o sK1 o q o p o g o sK0) –1
= sK0 o g -1 o p o q o sK1 o g -1 o p o sK2
We arrive at this expression since sKi is an XOR operation, which is its
own inverse. We have also specially chosen the constant
matrix in MixColumn, q such that the
inverse of MixColumn, q -1 is the same as MixColumn itself.
Since ShiftRow simply causes the second row to be rotated left by one nibble
amount, then the inverse of ShiftRow, p
-1 causes the second
row to be rotated right by one nibble. Rotating the nibble left or right are
one and the same operation because one row only has two nibbles, therefore
inverse ShiftRow is the same as ShiftRow. NibbleSub is a nibble substitution
operation based on Table 1. The inverse of Table 1 is easily computed by
interchanging the input nibble with the output nibble, and then resorting it
based on the new input nibble, as given in Table 3 below.
Input
|
Output
|
|
Input
|
Output
|
0000
|
1110
|
1000
|
0111
|
|
0001
|
0011
|
1001
|
1101
|
|
0010
|
0100
|
1010
|
1001
|
|
0011
|
1000
|
1011
|
0110
|
|
0100
|
0001
|
1100
|
1011
|
|
0101
|
1100
|
1101
|
0010
|
|
0110
|
1010
|
1110
|
0000
|
|
0111
|
1111
|
1111
|
0101
|
Table 3: Inverse S-box of
Mini-AES
For an input nibble, a0 = 1111, then
based on Table 1, the output nibble is b0 =
0111. To get back the original nibble a0 given the
value of b0, we use the inverse of Table 1, which
is Table
3. Referring
to Table 3, then given the input b0 = 0111, the
output is a0 = 1111.
Observe also that the order in which inverse NibbleSub, g -1 and
ShiftRow, p
is carried out is not important, since inverse NibbleSub operates on each
individual nibble whereas ShiftRow simply shifts the nibbles around. Hence, the
final expression for Mini- AES
decryption is:
Mini-AESDecrypt = sK0 o p o g -1 o q o sK1 o p
o g -1 o sK2
Comparing the expression for decryption and encryption, we see that they
are similar in structure, except that the round keys and the round constants
are applied in reverse order, and the NibbleSub component is replaced by its
inverse.
As an exercise, the student can try by pen and paper to
decrypt the ciphertext, H obtained in Example 9 to get back the original
plaintext, P.
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